Base | Representation |
---|---|
bin | 110000000000001101110000… |
… | …001101011010111100100000 |
3 | 1000200111222012111010200021220 |
4 | 300000031300031122330200 |
5 | 210133001302000020222 |
6 | 2025003352023015040 |
7 | 62316663122531232 |
oct | 6000156015327440 |
9 | 1020458174120256 |
10 | 211121000001312 |
11 | 612a6a05651145 |
12 | 1b8187b789a480 |
13 | 90a5817b07c3b |
14 | 3a1c44d250252 |
15 | 1961b1d3d0b5c |
hex | c0037035af20 |
211121000001312 has 48 divisors (see below), whose sum is σ = 572069806463232. Its totient is φ = 68103548386560.
The previous prime is 211121000001271. The next prime is 211121000001347. The reversal of 211121000001312 is 213100000121112.
It is a tau number, because it is divible by the number of its divisors (48).
It is a junction number, because it is equal to n+sod(n) for n = 211121000001291 and 211121000001300.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35470595143 + ... + 35470601094.
It is an arithmetic number, because the mean of its divisors is an integer number (11918120967984).
Almost surely, 2211121000001312 is an apocalyptic number.
It is an amenable number.
211121000001312 is an abundant number, since it is smaller than the sum of its proper divisors (360948806461920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211121000001312 is a wasteful number, since it uses less digits than its factorization.
211121000001312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70941196281 (or 70941196273 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 211121000001312 its reverse (213100000121112), we get a palindrome (424221000122424).
The spelling of 211121000001312 in words is "two hundred eleven trillion, one hundred twenty-one billion, one thousand, three hundred twelve".
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