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2112012119981 is a prime number
BaseRepresentation
bin11110101110111101101…
…110110110111110101101
321110220110202102010001102
4132232331232312332231
5234100400100314411
64254124525252445
7305405425546361
oct36567556667655
97426422363042
102112012119981
11744776866475
122a13a4704125
131242148900ca
1474316da52a1
1539e11a7dd3b
hex1ebbdbb6fad

2112012119981 has 2 divisors, whose sum is σ = 2112012119982. Its totient is φ = 2112012119980.

The previous prime is 2112012119963. The next prime is 2112012120019. The reversal of 2112012119981 is 1899112102112.

It is an a-pointer prime, because the next prime (2112012120019) can be obtained adding 2112012119981 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1798254180100 + 313757939881 = 1340990^2 + 560141^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112012119981 - 238 = 1837134213037 is a prime.

It is a super-2 number, since 2×21120121199812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112012119081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056006059990 + 1056006059991.

It is an arithmetic number, because the mean of its divisors is an integer number (1056006059991).

Almost surely, 22112012119981 is an apocalyptic number.

It is an amenable number.

2112012119981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112012119981 is an equidigital number, since it uses as much as digits as its factorization.

2112012119981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 38.

The spelling of 2112012119981 in words is "two trillion, one hundred twelve billion, twelve million, one hundred nineteen thousand, nine hundred eighty-one".