Base | Representation |
---|---|
bin | 11110101111000100011… |
… | …010111111111001100110 |
3 | 21110220202120121012101111 |
4 | 132233010122333321212 |
5 | 234101112313313100 |
6 | 4254144015015234 |
7 | 305411260534606 |
oct | 36570432777146 |
9 | 7426676535344 |
10 | 2112124354150 |
11 | 744824153688 |
12 | 2a141620a51a |
13 | 124231bc8365 |
14 | 74327c5cc06 |
15 | 39e1b84d6ba |
hex | 1ebc46bfe66 |
2112124354150 has 24 divisors (see below), whose sum is σ = 4024369626984. Its totient is φ = 824243649600.
The previous prime is 2112124354147. The next prime is 2112124354169. The reversal of 2112124354150 is 514534212112.
It is a super-3 number, since 3×21121243541503 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 515150232 + ... + 515154331.
It is an arithmetic number, because the mean of its divisors is an integer number (167682067791).
Almost surely, 22112124354150 is an apocalyptic number.
2112124354150 is a deficient number, since it is larger than the sum of its proper divisors (1912245272834).
2112124354150 is a wasteful number, since it uses less digits than its factorization.
2112124354150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1030304616 (or 1030304611 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 2112124354150 its reverse (514534212112), we get a palindrome (2626658566262).
The spelling of 2112124354150 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, three hundred fifty-four thousand, one hundred fifty".
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