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2112124354150 = 252411030304563
BaseRepresentation
bin11110101111000100011…
…010111111111001100110
321110220202120121012101111
4132233010122333321212
5234101112313313100
64254144015015234
7305411260534606
oct36570432777146
97426676535344
102112124354150
11744824153688
122a141620a51a
13124231bc8365
1474327c5cc06
1539e1b84d6ba
hex1ebc46bfe66

2112124354150 has 24 divisors (see below), whose sum is σ = 4024369626984. Its totient is φ = 824243649600.

The previous prime is 2112124354147. The next prime is 2112124354169. The reversal of 2112124354150 is 514534212112.

It is a super-3 number, since 3×21121243541503 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 515150232 + ... + 515154331.

It is an arithmetic number, because the mean of its divisors is an integer number (167682067791).

Almost surely, 22112124354150 is an apocalyptic number.

2112124354150 is a deficient number, since it is larger than the sum of its proper divisors (1912245272834).

2112124354150 is a wasteful number, since it uses less digits than its factorization.

2112124354150 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1030304616 (or 1030304611 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 2112124354150 its reverse (514534212112), we get a palindrome (2626658566262).

The spelling of 2112124354150 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, three hundred fifty-four thousand, one hundred fifty".

Divisors: 1 2 5 10 25 41 50 82 205 410 1025 2050 1030304563 2060609126 5151522815 10303045630 25757614075 42242487083 51515228150 84484974166 211212435415 422424870830 1056062177075 2112124354150