Base | Representation |
---|---|
bin | 110000000001100011100111… |
… | …111000001011011111000100 |
3 | 1000200211210012012111010100100 |
4 | 300001203213320023133010 |
5 | 210141004114203341400 |
6 | 2025114001104044100 |
7 | 62326436020640301 |
oct | 6001434770133704 |
9 | 1020753165433310 |
10 | 211213202012100 |
11 | 6133201a245562 |
12 | 1b83264a003630 |
13 | 90b141cbb3b82 |
14 | 3a22ab87900a8 |
15 | 1964217c25100 |
hex | c018e7e0b7c4 |
211213202012100 has 54 divisors (see below), whose sum is σ = 662036047642970. Its totient is φ = 56323520536320.
The previous prime is 211213202012089. The next prime is 211213202012101. The reversal of 211213202012100 is 1210202312112.
211213202012100 is a `hidden beast` number, since 2 + 1 + 121 + 320 + 201 + 21 + 0 + 0 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 226654070724 + 210986547941376 = 476082^2 + 14525376^2 .
It is a super-2 number, since 2×2112132020121002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (211213202012101) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 117340666885 + ... + 117340668684.
Almost surely, 2211213202012100 is an apocalyptic number.
211213202012100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211213202012100 is an abundant number, since it is smaller than the sum of its proper divisors (450822845630870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211213202012100 is a wasteful number, since it uses less digits than its factorization.
211213202012100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234681335589 (or 234681335579 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 211213202012100 its reverse (1210202312112), we get a palindrome (212423404324212).
The spelling of 211213202012100 in words is "two hundred eleven trillion, two hundred thirteen billion, two hundred two million, twelve thousand, one hundred".
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