Base | Representation |
---|---|
bin | 1100010010110110110… |
… | …1001000011110110000 |
3 | 202012012022002002001210 |
4 | 3010231231020132300 |
5 | 11430034333002230 |
6 | 241011102000120 |
7 | 21155143051251 |
oct | 3045555103660 |
9 | 665168062053 |
10 | 211220203440 |
11 | 8163a331104 |
12 | 34b29276040 |
13 | 16bc1a559cc |
14 | a31a312b28 |
15 | 576350deb0 |
hex | 312db487b0 |
211220203440 has 40 divisors (see below), whose sum is σ = 654782631408. Its totient is φ = 56325387520.
The previous prime is 211220203429. The next prime is 211220203459. The reversal of 211220203440 is 44302022112.
It is a tau number, because it is divible by the number of its divisors (40).
It is a super-3 number, since 3×2112202034403 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 440041851 + ... + 440042330.
Almost surely, 2211220203440 is an apocalyptic number.
211220203440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211220203440 is an abundant number, since it is smaller than the sum of its proper divisors (443562427968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211220203440 is a wasteful number, since it uses less digits than its factorization.
211220203440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 880084197 (or 880084191 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 211220203440 its reverse (44302022112), we get a palindrome (255522225552).
The spelling of 211220203440 in words is "two hundred eleven billion, two hundred twenty million, two hundred three thousand, four hundred forty".
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