Base | Representation |
---|---|
bin | 11110101111011100010… |
… | …010000001111100110111 |
3 | 21110221210110211122220012 |
4 | 132233130102001330313 |
5 | 234102422303001224 |
6 | 4254251434530435 |
7 | 305424221205641 |
oct | 36573422017467 |
9 | 7427713748805 |
10 | 2112524656439 |
11 | 744a0a10571a |
12 | 2a1508296a1b |
13 | 124296b14412 |
14 | 743650a1891 |
15 | 39e41a7180e |
hex | 1ebdc481f37 |
2112524656439 has 2 divisors, whose sum is σ = 2112524656440. Its totient is φ = 2112524656438.
The previous prime is 2112524656397. The next prime is 2112524656441. The reversal of 2112524656439 is 9346564252112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112524656439 is a prime.
Together with 2112524656441, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112524656339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056262328219 + 1056262328220.
It is an arithmetic number, because the mean of its divisors is an integer number (1056262328220).
Almost surely, 22112524656439 is an apocalyptic number.
2112524656439 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112524656439 is an equidigital number, since it uses as much as digits as its factorization.
2112524656439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3110400, while the sum is 50.
The spelling of 2112524656439 in words is "two trillion, one hundred twelve billion, five hundred twenty-four million, six hundred fifty-six thousand, four hundred thirty-nine".
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