Base | Representation |
---|---|
bin | 11110101111011100010… |
… | …010000001111100001101 |
3 | 21110221210110211122211122 |
4 | 132233130102001330031 |
5 | 234102422303001042 |
6 | 4254251434530325 |
7 | 305424221205551 |
oct | 36573422017415 |
9 | 7427713748748 |
10 | 2112524656397 |
11 | 744a0a105691 |
12 | 2a15082969a5 |
13 | 124296b143ac |
14 | 743650a1861 |
15 | 39e41a717d2 |
hex | 1ebdc481f0d |
2112524656397 has 2 divisors, whose sum is σ = 2112524656398. Its totient is φ = 2112524656396.
The previous prime is 2112524656373. The next prime is 2112524656439. The reversal of 2112524656397 is 7936564252112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1664768287081 + 447756369316 = 1290259^2 + 669146^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112524656397 - 214 = 2112524640013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112524656337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056262328198 + 1056262328199.
It is an arithmetic number, because the mean of its divisors is an integer number (1056262328199).
Almost surely, 22112524656397 is an apocalyptic number.
It is an amenable number.
2112524656397 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112524656397 is an equidigital number, since it uses as much as digits as its factorization.
2112524656397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5443200, while the sum is 53.
The spelling of 2112524656397 in words is "two trillion, one hundred twelve billion, five hundred twenty-four million, six hundred fifty-six thousand, three hundred ninety-seven".
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