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2113101047 is a prime number
BaseRepresentation
bin111110111110011…
…0101110011110111
312110021011122200202
41331330311303313
513311423213142
6545403031115
7103236030311
oct17574656367
95407148622
102113101047
11994877102
124ab80b49b
13278a27065
141608da7b1
15c57a4032
hex7df35cf7

2113101047 has 2 divisors, whose sum is σ = 2113101048. Its totient is φ = 2113101046.

The previous prime is 2113100993. The next prime is 2113101049. The reversal of 2113101047 is 7401013112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113101047 is a prime.

Together with 2113101049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113101049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056550523 + 1056550524.

It is an arithmetic number, because the mean of its divisors is an integer number (1056550524).

Almost surely, 22113101047 is an apocalyptic number.

2113101047 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113101047 is an equidigital number, since it uses as much as digits as its factorization.

2113101047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 2113101047 is about 45968.4788414844. The cubic root of 2113101047 is about 1283.2366507176.

Adding to 2113101047 its reverse (7401013112), we get a palindrome (9514114159).

The spelling of 2113101047 in words is "two billion, one hundred thirteen million, one hundred one thousand, forty-seven".