Base | Representation |
---|---|
bin | 1100010011001100111… |
… | …1100110100001011110 |
3 | 202012102202221000010110 |
4 | 3010303033212201132 |
5 | 11430232130003340 |
6 | 241024221350450 |
7 | 21160351634046 |
oct | 3046317464136 |
9 | 665382830113 |
10 | 211313125470 |
11 | 81687828877 |
12 | 34b54408426 |
13 | 16c0808b965 |
14 | a3287c0726 |
15 | 576b766680 |
hex | 31333e685e |
211313125470 has 32 divisors (see below), whose sum is σ = 519521052960. Its totient is φ = 54975772160.
The previous prime is 211313125453. The next prime is 211313125483. The reversal of 211313125470 is 74521313112.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85898415 + ... + 85900874.
It is an arithmetic number, because the mean of its divisors is an integer number (16235032905).
Almost surely, 2211313125470 is an apocalyptic number.
211313125470 is an abundant number, since it is smaller than the sum of its proper divisors (308207927490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211313125470 is a wasteful number, since it uses less digits than its factorization.
211313125470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171799340.
The product of its (nonzero) digits is 5040, while the sum is 30.
Adding to 211313125470 its reverse (74521313112), we get a palindrome (285834438582).
The spelling of 211313125470 in words is "two hundred eleven billion, three hundred thirteen million, one hundred twenty-five thousand, four hundred seventy".
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