Base | Representation |
---|---|
bin | 11110110000010000100… |
… | …010010010010011110101 |
3 | 21111001001120110110000202 |
4 | 132300100202102103311 |
5 | 234111221220123411 |
6 | 4254514433050245 |
7 | 305455024634141 |
oct | 36602042222365 |
9 | 7431046413022 |
10 | 2113401332981 |
11 | 745319a57794 |
12 | 2a17119b6985 |
13 | 1243a6632a33 |
14 | 744096aa221 |
15 | 39e939e283b |
hex | 1ec108924f5 |
2113401332981 has 2 divisors, whose sum is σ = 2113401332982. Its totient is φ = 2113401332980.
The previous prime is 2113401332941. The next prime is 2113401332983. The reversal of 2113401332981 is 1892331043112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1727623700881 + 385777632100 = 1314391^2 + 621110^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113401332981 is a prime.
It is a super-2 number, since 2×21134013329812 (a number of 25 digits) contains 22 as substring.
Together with 2113401332983, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113401332983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056700666490 + 1056700666491.
It is an arithmetic number, because the mean of its divisors is an integer number (1056700666491).
Almost surely, 22113401332981 is an apocalyptic number.
It is an amenable number.
2113401332981 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113401332981 is an equidigital number, since it uses as much as digits as its factorization.
2113401332981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 38.
The spelling of 2113401332981 in words is "two trillion, one hundred thirteen billion, four hundred one million, three hundred thirty-two thousand, nine hundred eighty-one".
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