Base | Representation |
---|---|
bin | 10011101011101100… |
… | …001100011001001111 |
3 | 2000112212112112001012 |
4 | 103223230030121033 |
5 | 321240312200142 |
6 | 13413041035435 |
7 | 1345502613014 |
oct | 235354143117 |
9 | 60485475035 |
10 | 21134100047 |
11 | 8a65715195 |
12 | 4119925b7b |
13 | 1cba637858 |
14 | 1046b7d70b |
15 | 83a5da882 |
hex | 4ebb0c64f |
21134100047 has 2 divisors, whose sum is σ = 21134100048. Its totient is φ = 21134100046.
The previous prime is 21134100023. The next prime is 21134100049. The reversal of 21134100047 is 74000143112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21134100047 - 26 = 21134099983 is a prime.
Together with 21134100049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21134099995 and 21134100031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21134100049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567050023 + 10567050024.
It is an arithmetic number, because the mean of its divisors is an integer number (10567050024).
Almost surely, 221134100047 is an apocalyptic number.
21134100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
21134100047 is an equidigital number, since it uses as much as digits as its factorization.
21134100047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 21134100047 its reverse (74000143112), we get a palindrome (95134243159).
The spelling of 21134100047 in words is "twenty-one billion, one hundred thirty-four million, one hundred thousand, forty-seven".
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