Base | Representation |
---|---|
bin | 1100010011010100001… |
… | …0110100101101011100 |
3 | 202012111212202120010221 |
4 | 3010311002310231130 |
5 | 11430312343031030 |
6 | 241031221011124 |
7 | 21161166444235 |
oct | 3046502645534 |
9 | 665455676127 |
10 | 211343330140 |
11 | 816a2889008 |
12 | 34b62553aa4 |
13 | 16c11405b47 |
14 | a32c80408c |
15 | 576e230e7a |
hex | 31350b4b5c |
211343330140 has 24 divisors (see below), whose sum is σ = 444822865200. Its totient is φ = 84346499328.
The previous prime is 211343330137. The next prime is 211343330161. The reversal of 211343330140 is 41033343112.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11917965 + ... + 11935684.
It is an arithmetic number, because the mean of its divisors is an integer number (18534286050).
Almost surely, 2211343330140 is an apocalyptic number.
211343330140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211343330140 is an abundant number, since it is smaller than the sum of its proper divisors (233479535060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211343330140 is a wasteful number, since it uses less digits than its factorization.
211343330140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23854101 (or 23854099 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 211343330140 its reverse (41033343112), we get a palindrome (252376673252).
The spelling of 211343330140 in words is "two hundred eleven billion, three hundred forty-three million, three hundred thirty thousand, one hundred forty".
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