Base | Representation |
---|---|
bin | 10011101100001010… |
… | …110010100000010111 |
3 | 2000120102121222222221 |
4 | 103230022302200113 |
5 | 321244340323341 |
6 | 13413525003211 |
7 | 1345631026123 |
oct | 235412624027 |
9 | 60512558887 |
10 | 21142120471 |
11 | 8a6a1a303a |
12 | 4120553507 |
13 | 1cbc1b5374 |
14 | 1047c6a583 |
15 | 83b171ed1 |
hex | 4ec2b2817 |
21142120471 has 2 divisors, whose sum is σ = 21142120472. Its totient is φ = 21142120470.
The previous prime is 21142120463. The next prime is 21142120501. The reversal of 21142120471 is 17402124112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21142120471 - 23 = 21142120463 is a prime.
It is a super-3 number, since 3×211421204713 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21142120411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571060235 + 10571060236.
It is an arithmetic number, because the mean of its divisors is an integer number (10571060236).
Almost surely, 221142120471 is an apocalyptic number.
21142120471 is a deficient number, since it is larger than the sum of its proper divisors (1).
21142120471 is an equidigital number, since it uses as much as digits as its factorization.
21142120471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 21142120471 its reverse (17402124112), we get a palindrome (38544244583).
The spelling of 21142120471 in words is "twenty-one billion, one hundred forty-two million, one hundred twenty thousand, four hundred seventy-one".
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