Base | Representation |
---|---|
bin | 1001100111010101111110… |
… | …00011001001011000110010 |
3 | 2202212020212102011102112110 |
4 | 10303222333003021120302 |
5 | 10232401413240212200 |
6 | 112544550442110150 |
7 | 4311351046215501 |
oct | 463527703113062 |
9 | 82766772142473 |
10 | 21143034304050 |
11 | 681178a73766a |
12 | 24557b34ab356 |
13 | ba4a19976b39 |
14 | 531484ca8838 |
15 | 269ea38dbb50 |
hex | 133abf0c9632 |
21143034304050 has 48 divisors (see below), whose sum is σ = 53173242355392. Its totient is φ = 5558732020800.
The previous prime is 21143034304039. The next prime is 21143034304087. The reversal of 21143034304050 is 5040343034112.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 21143034303999 and 21143034304017.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 992620069 + ... + 992641368.
It is an arithmetic number, because the mean of its divisors is an integer number (1107775882404).
Almost surely, 221143034304050 is an apocalyptic number.
21143034304050 is an abundant number, since it is smaller than the sum of its proper divisors (32030208051342).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21143034304050 is a wasteful number, since it uses less digits than its factorization.
21143034304050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1985261523 (or 1985261518 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 21143034304050 its reverse (5040343034112), we get a palindrome (26183377338162).
The spelling of 21143034304050 in words is "twenty-one trillion, one hundred forty-three billion, thirty-four million, three hundred four thousand, fifty".
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