Base | Representation |
---|---|
bin | 11110110110011010100… |
… | …000111110000111000111 |
3 | 21111200010020010001100102 |
4 | 132312122200332013013 |
5 | 234213240332224312 |
6 | 4301530353434315 |
7 | 306110565653141 |
oct | 36663240760707 |
9 | 7450106101312 |
10 | 2120011211207 |
11 | 74810107306a |
12 | 2a2a5756b99b |
13 | 124bbab75696 |
14 | 748754b3c91 |
15 | 3a22de49ec2 |
hex | 1ed9a83e1c7 |
2120011211207 has 2 divisors, whose sum is σ = 2120011211208. Its totient is φ = 2120011211206.
The previous prime is 2120011211177. The next prime is 2120011211231. The reversal of 2120011211207 is 7021121100212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2120011211207 - 214 = 2120011194823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2120011271207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060005605603 + 1060005605604.
It is an arithmetic number, because the mean of its divisors is an integer number (1060005605604).
Almost surely, 22120011211207 is an apocalyptic number.
2120011211207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120011211207 is an equidigital number, since it uses as much as digits as its factorization.
2120011211207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 2120011211207 its reverse (7021121100212), we get a palindrome (9141132311419).
The spelling of 2120011211207 in words is "two trillion, one hundred twenty billion, eleven million, two hundred eleven thousand, two hundred seven".
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