Base | Representation |
---|---|
bin | 11110110110100000000… |
… | …011010110111110001101 |
3 | 21111200100200220220022000 |
4 | 132312200003112332031 |
5 | 234213433123041023 |
6 | 4301543512542513 |
7 | 306113104420026 |
oct | 36664003267615 |
9 | 7450320826260 |
10 | 2120104112013 |
11 | 748149555898 |
12 | 2a2a826b1a39 |
13 | 124c041a1a84 |
14 | 74883977c4d |
15 | 3a23719b243 |
hex | 1eda00d6f8d |
2120104112013 has 64 divisors (see below), whose sum is σ = 3441233030400. Its totient is φ = 1284724869120.
The previous prime is 2120104111997. The next prime is 2120104112017. The reversal of 2120104112013 is 3102114010212.
2120104112013 is a `hidden beast` number, since 21 + 20 + 10 + 411 + 201 + 3 = 666.
It is not a de Polignac number, because 2120104112013 - 24 = 2120104111997 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2120104112017) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1153123 + ... + 2360063.
It is an arithmetic number, because the mean of its divisors is an integer number (53769266100).
Almost surely, 22120104112013 is an apocalyptic number.
It is an amenable number.
2120104112013 is a deficient number, since it is larger than the sum of its proper divisors (1321128918387).
2120104112013 is a wasteful number, since it uses less digits than its factorization.
2120104112013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1207099 (or 1207093 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 2120104112013 its reverse (3102114010212), we get a palindrome (5222218122225).
The spelling of 2120104112013 in words is "two trillion, one hundred twenty billion, one hundred four million, one hundred twelve thousand, thirteen".
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