Search a number
-
+
21201101002013 is a prime number
BaseRepresentation
bin1001101001000010001000…
…00110000001010100011101
32210001210202011220022110112
410310201010012001110131
510234324323324031023
6113031352405015405
74315505022053222
oct464410406012435
983053664808415
1021201101002013
116834377893249
122464ab99b4565
13baa341a1050a
145341d2aa5949
1526b751554478
hex13484418151d

21201101002013 has 2 divisors, whose sum is σ = 21201101002014. Its totient is φ = 21201101002012.

The previous prime is 21201101001989. The next prime is 21201101002027. The reversal of 21201101002013 is 31020010110212.

It is an a-pointer prime, because the next prime (21201101002027) can be obtained adding 21201101002013 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13002969157369 + 8198131844644 = 3605963^2 + 2863238^2 .

It is a cyclic number.

It is not a de Polignac number, because 21201101002013 - 214 = 21201100985629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21201101002033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600550501006 + 10600550501007.

It is an arithmetic number, because the mean of its divisors is an integer number (10600550501007).

Almost surely, 221201101002013 is an apocalyptic number.

It is an amenable number.

21201101002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

21201101002013 is an equidigital number, since it uses as much as digits as its factorization.

21201101002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 21201101002013 its reverse (31020010110212), we get a palindrome (52221111112225).

The spelling of 21201101002013 in words is "twenty-one trillion, two hundred one billion, one hundred one million, two thousand, thirteen".