Base | Representation |
---|---|
bin | 1001101001000010001000… |
… | …01010001101101010001011 |
3 | 2210001210202020222011011121 |
4 | 10310201010022031222023 |
5 | 10234324324114214011 |
6 | 113031352444340111 |
7 | 4315505034311521 |
oct | 464410412155213 |
9 | 83053666864147 |
10 | 21201102101131 |
11 | 6834378474007 |
12 | 2464aba244637 |
13 | baa342006894 |
14 | 5341d2cb0311 |
15 | 26b7516bee71 |
hex | 13484428da8b |
21201102101131 has 2 divisors, whose sum is σ = 21201102101132. Its totient is φ = 21201102101130.
The previous prime is 21201102101129. The next prime is 21201102101149. The reversal of 21201102101131 is 13110120110212.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21201102101131 - 21 = 21201102101129 is a prime.
It is a super-2 number, since 2×212011021011312 (a number of 27 digits) contains 22 as substring.
Together with 21201102101129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (21201102104131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600551050565 + 10600551050566.
It is an arithmetic number, because the mean of its divisors is an integer number (10600551050566).
Almost surely, 221201102101131 is an apocalyptic number.
21201102101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21201102101131 is an equidigital number, since it uses as much as digits as its factorization.
21201102101131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 21201102101131 its reverse (13110120110212), we get a palindrome (34311222211343).
The spelling of 21201102101131 in words is "twenty-one trillion, two hundred one billion, one hundred two million, one hundred one thousand, one hundred thirty-one".
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