Base | Representation |
---|---|
bin | 1001101001000010110001… |
… | …00010011101010110011111 |
3 | 2210001211122002022110212111 |
4 | 10310201120202131112133 |
5 | 10234331024131014213 |
6 | 113031450420414451 |
7 | 4315516355361625 |
oct | 464413042352637 |
9 | 83054562273774 |
10 | 21201444001183 |
11 | 6834533466636 |
12 | 2464b94847427 |
13 | baa397ab4cc4 |
14 | 53422646d515 |
15 | 26b771708a3d |
hex | 13485889d59f |
21201444001183 has 2 divisors, whose sum is σ = 21201444001184. Its totient is φ = 21201444001182.
The previous prime is 21201444001181. The next prime is 21201444001189. The reversal of 21201444001183 is 38110044410212.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21201444001183 - 21 = 21201444001181 is a prime.
Together with 21201444001181, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21201444001181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600722000591 + 10600722000592.
It is an arithmetic number, because the mean of its divisors is an integer number (10600722000592).
Almost surely, 221201444001183 is an apocalyptic number.
21201444001183 is a deficient number, since it is larger than the sum of its proper divisors (1).
21201444001183 is an equidigital number, since it uses as much as digits as its factorization.
21201444001183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 21201444001183 its reverse (38110044410212), we get a palindrome (59311488411395).
The spelling of 21201444001183 in words is "twenty-one trillion, two hundred one billion, four hundred forty-four million, one thousand, one hundred eighty-three".
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