Base | Representation |
---|---|
bin | 110000001110011110101001… |
… | …010110011100100110101111 |
3 | 1000210222200022002110110101221 |
4 | 300032132221112130212233 |
5 | 210300031240032242312 |
6 | 2031033541251044211 |
7 | 62450543511412462 |
oct | 6016365126344657 |
9 | 1023880262413357 |
10 | 212101211212207 |
11 | 61644689297979 |
12 | 1b9567765a0667 |
13 | 914709b3a9bc5 |
14 | 3a53a794712d9 |
15 | 197c38c6ec207 |
hex | c0e7a959c9af |
212101211212207 has 2 divisors, whose sum is σ = 212101211212208. Its totient is φ = 212101211212206.
The previous prime is 212101211212199. The next prime is 212101211212211. The reversal of 212101211212207 is 702212112101212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212101211212207 - 23 = 212101211212199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212101211212277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106050605606103 + 106050605606104.
It is an arithmetic number, because the mean of its divisors is an integer number (106050605606104).
Almost surely, 2212101211212207 is an apocalyptic number.
212101211212207 is a deficient number, since it is larger than the sum of its proper divisors (1).
212101211212207 is an equidigital number, since it uses as much as digits as its factorization.
212101211212207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 212101211212207 its reverse (702212112101212), we get a palindrome (914313323313419).
The spelling of 212101211212207 in words is "two hundred twelve trillion, one hundred one billion, two hundred eleven million, two hundred twelve thousand, two hundred seven".
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