Base | Representation |
---|---|
bin | 1001101001010110100100… |
… | …01110000010110000110111 |
3 | 2210002212002000011201022002 |
4 | 10310223102032002300313 |
5 | 10240014312300414333 |
6 | 113040405400325515 |
7 | 4316344000664255 |
oct | 464532216026067 |
9 | 83085060151262 |
10 | 21212075404343 |
11 | 6838a9962813a |
12 | 246706117389b |
13 | bab3a05448c5 |
14 | 5349543d15d5 |
15 | 26bb94c390e8 |
hex | 134ad2382c37 |
21212075404343 has 2 divisors, whose sum is σ = 21212075404344. Its totient is φ = 21212075404342.
The previous prime is 21212075404337. The next prime is 21212075404381. The reversal of 21212075404343 is 34340457021212.
It is an a-pointer prime, because the next prime (21212075404381) can be obtained adding 21212075404343 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21212075404343 - 26 = 21212075404279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21212075404297 and 21212075404306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21212075407343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606037702171 + 10606037702172.
It is an arithmetic number, because the mean of its divisors is an integer number (10606037702172).
Almost surely, 221212075404343 is an apocalyptic number.
21212075404343 is a deficient number, since it is larger than the sum of its proper divisors (1).
21212075404343 is an equidigital number, since it uses as much as digits as its factorization.
21212075404343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 38.
The spelling of 21212075404343 in words is "twenty-one trillion, two hundred twelve billion, seventy-five million, four hundred four thousand, three hundred forty-three".
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