Base | Representation |
---|---|
bin | 110000001110110011111111… |
… | …100100010100000100001100 |
3 | 1000211001212110111221202110212 |
4 | 300032303333210110010030 |
5 | 210300420210411234200 |
6 | 2031052251534221552 |
7 | 62452314515352323 |
oct | 6016637744240414 |
9 | 1024055414852425 |
10 | 212124132524300 |
11 | 61653380821a07 |
12 | 1b95b0b29548b8 |
13 | 91492b2077c79 |
14 | 3a54c117190ba |
15 | 197cc7eb67035 |
hex | c0ecff91410c |
212124132524300 has 36 divisors (see below), whose sum is σ = 468994449996576. Its totient is φ = 83248716158400.
The previous prime is 212124132524251. The next prime is 212124132524309. The reversal of 212124132524300 is 3425231421212.
It is not an unprimeable number, because it can be changed into a prime (212124132524309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20011705316 + ... + 20011715915.
It is an arithmetic number, because the mean of its divisors is an integer number (13027623611016).
Almost surely, 2212124132524300 is an apocalyptic number.
212124132524300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
212124132524300 is an abundant number, since it is smaller than the sum of its proper divisors (256870317472276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212124132524300 is a wasteful number, since it uses less digits than its factorization.
212124132524300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40023421298 (or 40023421291 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 212124132524300 its reverse (3425231421212), we get a palindrome (215549363945512).
The spelling of 212124132524300 in words is "two hundred twelve trillion, one hundred twenty-four billion, one hundred thirty-two million, five hundred twenty-four thousand, three hundred".
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