Base | Representation |
---|---|
bin | 11110110111101000000… |
… | …110111001101001100111 |
3 | 21111210110221122202220121 |
4 | 132313220012321221213 |
5 | 234223422112000124 |
6 | 4302303455342411 |
7 | 306155053663642 |
oct | 36675006715147 |
9 | 7453427582817 |
10 | 2121313000039 |
11 | 748709982302 |
12 | 2a315b521a07 |
13 | 12506778892c |
14 | 7495a33ca59 |
15 | 3a2a83902e4 |
hex | 1ede81b9a67 |
2121313000039 has 2 divisors, whose sum is σ = 2121313000040. Its totient is φ = 2121313000038.
The previous prime is 2121313000021. The next prime is 2121313000117. The reversal of 2121313000039 is 9300003131212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2121313000039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2121312999977 and 2121313000022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121313000739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060656500019 + 1060656500020.
It is an arithmetic number, because the mean of its divisors is an integer number (1060656500020).
Almost surely, 22121313000039 is an apocalyptic number.
2121313000039 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121313000039 is an equidigital number, since it uses as much as digits as its factorization.
2121313000039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 2121313000039 in words is "two trillion, one hundred twenty-one billion, three hundred thirteen million, thirty-nine", and thus it is an aban number.
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