Base | Representation |
---|---|
bin | 1100010110010000000… |
… | …1001100010001100111 |
3 | 202021112210201021000012 |
4 | 3011210001030101213 |
5 | 11433421121302102 |
6 | 241241332440435 |
7 | 21216546263021 |
oct | 3054401142147 |
9 | 667483637005 |
10 | 212131431527 |
11 | 81a67732274 |
12 | 3514247911b |
13 | 17008780c22 |
14 | a3a5353011 |
15 | 57b8507752 |
hex | 316404c467 |
212131431527 has 2 divisors, whose sum is σ = 212131431528. Its totient is φ = 212131431526.
The previous prime is 212131431443. The next prime is 212131431529. The reversal of 212131431527 is 725134131212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212131431527 - 28 = 212131431271 is a prime.
Together with 212131431529, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 212131431493 and 212131431502.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212131431529) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106065715763 + 106065715764.
It is an arithmetic number, because the mean of its divisors is an integer number (106065715764).
Almost surely, 2212131431527 is an apocalyptic number.
212131431527 is a deficient number, since it is larger than the sum of its proper divisors (1).
212131431527 is an equidigital number, since it uses as much as digits as its factorization.
212131431527 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10080, while the sum is 32.
Adding to 212131431527 its reverse (725134131212), we get a palindrome (937265562739).
The spelling of 212131431527 in words is "two hundred twelve billion, one hundred thirty-one million, four hundred thirty-one thousand, five hundred twenty-seven".
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