Base | Representation |
---|---|
bin | 110000001110111100010110… |
… | …010000000001010011000111 |
3 | 1000211002201121200111220111021 |
4 | 300032330112100001103013 |
5 | 210301042043332440421 |
6 | 2031100334023052011 |
7 | 62453053022310625 |
oct | 6016742620012307 |
9 | 1024081550456437 |
10 | 212133103015111 |
11 | 61657164398483 |
12 | 1b960996ba1007 |
13 | 914a0b16957b5 |
14 | 3a55422c4c515 |
15 | 197d107465341 |
hex | c0ef164014c7 |
212133103015111 has 2 divisors, whose sum is σ = 212133103015112. Its totient is φ = 212133103015110.
The previous prime is 212133103015109. The next prime is 212133103015231. The reversal of 212133103015111 is 111510301331212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212133103015111 - 21 = 212133103015109 is a prime.
Together with 212133103015109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212133103015811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106066551507555 + 106066551507556.
It is an arithmetic number, because the mean of its divisors is an integer number (106066551507556).
Almost surely, 2212133103015111 is an apocalyptic number.
212133103015111 is a deficient number, since it is larger than the sum of its proper divisors (1).
212133103015111 is an equidigital number, since it uses as much as digits as its factorization.
212133103015111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 212133103015111 its reverse (111510301331212), we get a palindrome (323643404346323).
The spelling of 212133103015111 in words is "two hundred twelve trillion, one hundred thirty-three billion, one hundred three million, fifteen thousand, one hundred eleven".
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