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212133330121997 is a prime number
BaseRepresentation
bin110000001110111100100011…
…110010010111010100001101
31000211002202012111212010120102
4300032330203302113110031
5210301043030002400442
62031100412334500445
762453061450554054
oct6016744362272415
91024082174763512
10212133330121997
1161657270605219
121b960a3b064725
13914a119750c7b
143a5544508939b
15197d11c376232
hexc0ef23c9750d

212133330121997 has 2 divisors, whose sum is σ = 212133330121998. Its totient is φ = 212133330121996.

The previous prime is 212133330121969. The next prime is 212133330122003. The reversal of 212133330121997 is 799121033331212.

It is a happy number.

212133330121997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 191259661671556 + 20873668450441 = 13829666^2 + 4568771^2 .

It is a cyclic number.

It is not a de Polignac number, because 212133330121997 - 240 = 211033818494221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212133330421997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106066665060998 + 106066665060999.

It is an arithmetic number, because the mean of its divisors is an integer number (106066665060999).

Almost surely, 2212133330121997 is an apocalyptic number.

It is an amenable number.

212133330121997 is a deficient number, since it is larger than the sum of its proper divisors (1).

212133330121997 is an equidigital number, since it uses as much as digits as its factorization.

212133330121997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 367416, while the sum is 47.

The spelling of 212133330121997 in words is "two hundred twelve trillion, one hundred thirty-three billion, three hundred thirty million, one hundred twenty-one thousand, nine hundred ninety-seven".