Base | Representation |
---|---|
bin | 11110111000011101100… |
… | …101100001100001001111 |
3 | 21111212210110221021110122 |
4 | 132320131211201201033 |
5 | 234232241304020421 |
6 | 4302532510055155 |
7 | 306216230143622 |
oct | 36703545414117 |
9 | 7455713837418 |
10 | 2122210220111 |
11 | 74902a385aa3 |
12 | 2a336baaa4bb |
13 | 12517b61ab97 |
14 | 74a03573db9 |
15 | 3a30c01d2ab |
hex | 1ee1d96184f |
2122210220111 has 2 divisors, whose sum is σ = 2122210220112. Its totient is φ = 2122210220110.
The previous prime is 2122210220101. The next prime is 2122210220113. The reversal of 2122210220111 is 1110220122212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2122210220111 is a prime.
Together with 2122210220113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2122210220111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2122210220113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061105110055 + 1061105110056.
It is an arithmetic number, because the mean of its divisors is an integer number (1061105110056).
Almost surely, 22122210220111 is an apocalyptic number.
2122210220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122210220111 is an equidigital number, since it uses as much as digits as its factorization.
2122210220111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 2122210220111 its reverse (1110220122212), we get a palindrome (3232430342323).
The spelling of 2122210220111 in words is "two trillion, one hundred twenty-two billion, two hundred ten million, two hundred twenty thousand, one hundred eleven".
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