Base | Representation |
---|---|
bin | 1100010110101011000… |
… | …0100000111010011101 |
3 | 202021211200110201222001 |
4 | 3011222300200322131 |
5 | 11434134043001000 |
6 | 241300452122301 |
7 | 21222421325050 |
oct | 3055260407235 |
9 | 667750421861 |
10 | 212244500125 |
11 | 8201553a399 |
12 | 35174306391 |
13 | 1702601bc18 |
14 | a3b6386a97 |
15 | 57c33de46a |
hex | 316ac20e9d |
212244500125 has 64 divisors (see below), whose sum is σ = 310371909120. Its totient is φ = 141867072000.
The previous prime is 212244500099. The next prime is 212244500161. The reversal of 212244500125 is 521005442212.
It is a happy number.
It is not a de Polignac number, because 212244500125 - 213 = 212244491933 is a prime.
It is a super-2 number, since 2×2122445001252 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212244500093 and 212244500102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 64178722 + ... + 64182028.
It is an arithmetic number, because the mean of its divisors is an integer number (4849561080).
Almost surely, 2212244500125 is an apocalyptic number.
212244500125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
212244500125 is a deficient number, since it is larger than the sum of its proper divisors (98127408995).
212244500125 is a wasteful number, since it uses less digits than its factorization.
212244500125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5159 (or 5149 counting only the distinct ones).
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 212244500125 its reverse (521005442212), we get a palindrome (733249942337).
The spelling of 212244500125 in words is "two hundred twelve billion, two hundred forty-four million, five hundred thousand, one hundred twenty-five".
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