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212292511229 is a prime number
BaseRepresentation
bin1100010110110110011…
…1101010010111111101
3202021222000210221211002
43011231213222113331
511434233340324404
6241305325140045
721223543400111
oct3055547522775
9667860727732
10212292511229
118203a651897
12351883ba625
1317032c5bc66
14a3bc8c3741
1557c7724c1e
hex316d9ea5fd

212292511229 has 2 divisors, whose sum is σ = 212292511230. Its totient is φ = 212292511228.

The previous prime is 212292511177. The next prime is 212292511231. The reversal of 212292511229 is 922115292212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141801199225 + 70491312004 = 376565^2 + 265502^2 .

It is a cyclic number.

It is not a de Polignac number, because 212292511229 - 228 = 212024075773 is a prime.

It is a super-2 number, since 2×2122925112292 (a number of 23 digits) contains 22 as substring.

Together with 212292511231, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 212292511192 and 212292511201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212292511259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106146255614 + 106146255615.

It is an arithmetic number, because the mean of its divisors is an integer number (106146255615).

Almost surely, 2212292511229 is an apocalyptic number.

It is an amenable number.

212292511229 is a deficient number, since it is larger than the sum of its proper divisors (1).

212292511229 is an equidigital number, since it uses as much as digits as its factorization.

212292511229 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25920, while the sum is 38.

The spelling of 212292511229 in words is "two hundred twelve billion, two hundred ninety-two million, five hundred eleven thousand, two hundred twenty-nine".