Base | Representation |
---|---|
bin | 110000010001011010001100… |
… | …000100100010011011010111 |
3 | 1000211200221002001211121002002 |
4 | 300101122030010202123113 |
5 | 210311331142330103421 |
6 | 2031310243240505515 |
7 | 62501232634206032 |
oct | 6021321404423327 |
9 | 1024627061747062 |
10 | 212302583441111 |
11 | 617120246a9a49 |
12 | 1b9897b577b29b |
13 | 9160080aa3237 |
14 | 3a5d6dd8b6019 |
15 | 198272637cb0b |
hex | c1168c1226d7 |
212302583441111 has 2 divisors, whose sum is σ = 212302583441112. Its totient is φ = 212302583441110.
The previous prime is 212302583441083. The next prime is 212302583441149. The reversal of 212302583441111 is 111144385203212.
It is an a-pointer prime, because the next prime (212302583441149) can be obtained adding 212302583441111 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212302583441111 - 218 = 212302583178967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212302583441161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106151291720555 + 106151291720556.
It is an arithmetic number, because the mean of its divisors is an integer number (106151291720556).
Almost surely, 2212302583441111 is an apocalyptic number.
212302583441111 is a deficient number, since it is larger than the sum of its proper divisors (1).
212302583441111 is an equidigital number, since it uses as much as digits as its factorization.
212302583441111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 38.
The spelling of 212302583441111 in words is "two hundred twelve trillion, three hundred two billion, five hundred eighty-three million, four hundred forty-one thousand, one hundred eleven".
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