Base | Representation |
---|---|
bin | 1001101010100011100011… |
… | …01010110000001001110111 |
3 | 2210020210202100111112202021 |
4 | 10311101301222300021313 |
5 | 10241203433213311203 |
6 | 113111402441454011 |
7 | 4322336123400154 |
oct | 465216152601167 |
9 | 83223670445667 |
10 | 21253405213303 |
11 | 685457819334a |
12 | 24730764a1307 |
13 | bb2258c6b173 |
14 | 53695543d22b |
15 | 26ccb334d5bd |
hex | 135471ab0277 |
21253405213303 has 2 divisors, whose sum is σ = 21253405213304. Its totient is φ = 21253405213302.
The previous prime is 21253405213301. The next prime is 21253405213321. The reversal of 21253405213303 is 30331250435212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21253405213303 - 21 = 21253405213301 is a prime.
Together with 21253405213301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21253405213301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10626702606651 + 10626702606652.
It is an arithmetic number, because the mean of its divisors is an integer number (10626702606652).
Almost surely, 221253405213303 is an apocalyptic number.
21253405213303 is a deficient number, since it is larger than the sum of its proper divisors (1).
21253405213303 is an equidigital number, since it uses as much as digits as its factorization.
21253405213303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 21253405213303 its reverse (30331250435212), we get a palindrome (51584655648515).
The spelling of 21253405213303 in words is "twenty-one trillion, two hundred fifty-three billion, four hundred five million, two hundred thirteen thousand, three hundred three".
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