Base | Representation |
---|---|
bin | 1001101011101010011011… |
… | …11001010010001010000000 |
3 | 2210101102222102211020020001 |
4 | 10311311031321102022000 |
5 | 10242314402143422410 |
6 | 113141054522325344 |
7 | 4325154135532645 |
oct | 465651571221200 |
9 | 83342872736201 |
10 | 21291459748480 |
11 | 6869725a62919 |
12 | 247a516959854 |
13 | bb5a11c5babc |
14 | 5387254a9dcc |
15 | 26dc8e14633a |
hex | 135d4de52280 |
21291459748480 has 64 divisors (see below), whose sum is σ = 50900691045600. Its totient is φ = 8516450866176.
The previous prime is 21291459748453. The next prime is 21291459748513. The reversal of 21291459748480 is 8484795419212.
It is a tau number, because it is divible by the number of its divisors (64).
It is a super-3 number, since 3×212914597484803 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (64).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47636119 + ... + 48081001.
Almost surely, 221291459748480 is an apocalyptic number.
21291459748480 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21291459748480 is an abundant number, since it is smaller than the sum of its proper divisors (29609231297120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21291459748480 is an equidigital number, since it uses as much as digits as its factorization.
21291459748480 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 519681 (or 519669 counting only the distinct ones).
The product of its (nonzero) digits is 46448640, while the sum is 64.
The spelling of 21291459748480 in words is "twenty-one trillion, two hundred ninety-one billion, four hundred fifty-nine million, seven hundred forty-eight thousand, four hundred eighty".
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