Base | Representation |
---|---|
bin | 111111011101100… |
… | …0100101111011101 |
3 | 12111101212111102011 |
4 | 1332323010233131 |
5 | 13330112241013 |
6 | 551144431221 |
7 | 103524505246 |
oct | 17673045735 |
9 | 5441774364 |
10 | 2129415133 |
11 | 9a2aaa11a |
12 | 4b5178511 |
13 | 27c219871 |
14 | 162b45ccd |
15 | c6e27c3d |
hex | 7eec4bdd |
2129415133 has 2 divisors, whose sum is σ = 2129415134. Its totient is φ = 2129415132.
The previous prime is 2129415131. The next prime is 2129415143. The reversal of 2129415133 is 3315149212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1608571449 + 520843684 = 40107^2 + 22822^2 .
It is a cyclic number.
It is not a de Polignac number, because 2129415133 - 21 = 2129415131 is a prime.
Together with 2129415131, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 2129415095 and 2129415104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2129415131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1064707566 + 1064707567.
It is an arithmetic number, because the mean of its divisors is an integer number (1064707567).
Almost surely, 22129415133 is an apocalyptic number.
It is an amenable number.
2129415133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2129415133 is an equidigital number, since it uses as much as digits as its factorization.
2129415133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6480, while the sum is 31.
The square root of 2129415133 is about 46145.5862786464. The cubic root of 2129415133 is about 1286.5305754728.
The spelling of 2129415133 in words is "two billion, one hundred twenty-nine million, four hundred fifteen thousand, one hundred thirty-three".
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