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213101311200120 = 23335728188004127
BaseRepresentation
bin110000011101000010000011…
…111101001000101101111000
31000221112021201210000210112000
4300131002003331020231320
5210412422441131400440
62033121220232421000
762613030102143460
oct6035020375105570
91027467653023460
10213101311200120
116199a8386a6202
121ba98565b47760
1391ba4a12b3895
143a8a230ca4ba0
1519983c2b14730
hexc1d083f48b78

213101311200120 has 128 divisors (see below), whose sum is σ = 811814518886400. Its totient is φ = 48708871129728.

The previous prime is 213101311200109. The next prime is 213101311200121. The reversal of 213101311200120 is 21002113101312.

213101311200120 is a `hidden beast` number, since 2 + 1 + 31 + 0 + 1 + 311 + 200 + 120 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 213101311200093 and 213101311200102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213101311200121) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14093994504 + ... + 14094009623.

It is an arithmetic number, because the mean of its divisors is an integer number (6342300928800).

Almost surely, 2213101311200120 is an apocalyptic number.

213101311200120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

213101311200120 is an abundant number, since it is smaller than the sum of its proper divisors (598713207686280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213101311200120 is a wasteful number, since it uses less digits than its factorization.

213101311200120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28188004154 (or 28188004144 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 213101311200120 its reverse (21002113101312), we get a palindrome (234103424301432).

The spelling of 213101311200120 in words is "two hundred thirteen trillion, one hundred one billion, three hundred eleven million, two hundred thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 7 8 9 10 12 14 15 18 20 21 24 27 28 30 35 36 40 42 45 54 56 60 63 70 72 84 90 105 108 120 126 135 140 168 180 189 210 216 252 270 280 315 360 378 420 504 540 630 756 840 945 1080 1260 1512 1890 2520 3780 7560 28188004127 56376008254 84564012381 112752016508 140940020635 169128024762 197316028889 225504033016 253692037143 281880041270 338256049524 394632057778 422820061905 507384074286 563760082540 591948086667 676512099048 761076111429 789264115556 845640123810 986580144445 1014768148572 1127520165080 1183896173334 1268460185715 1522152222858 1578528231112 1691280247620 1775844260001 1973160288890 2029536297144 2367792346668 2536920371430 2959740433335 3044304445716 3382560495240 3551688520002 3805380557145 3946320577780 4735584693336 5073840742860 5327532780003 5919480866670 6088608891432 7103377040004 7610761114290 7892641155560 8879221300005 10147681485720 10655065560006 11838961733340 14206754080008 15221522228580 17758442600010 21310131120012 23677923466680 26637663900015 30443044457160 35516885200020 42620262240024 53275327800030 71033770400040 106550655600060 213101311200120