Base | Representation |
---|---|
bin | 1100011001110111110… |
… | …1000101011011100000 |
3 | 202101001112201001222001 |
4 | 3012131331011123200 |
5 | 11442413434332230 |
6 | 241522014053344 |
7 | 21252621203602 |
oct | 3063575053340 |
9 | 671045631861 |
10 | 213103433440 |
11 | 82416372737 |
12 | 35373aaa254 |
13 | 17131c673a1 |
14 | a458493172 |
15 | 5823a080ca |
hex | 319df456e0 |
213103433440 has 24 divisors (see below), whose sum is σ = 503456861880. Its totient is φ = 85241373312.
The previous prime is 213103433351. The next prime is 213103433441. The reversal of 213103433440 is 44334301312.
It is a junction number, because it is equal to n+sod(n) for n = 213103433399 and 213103433408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213103433441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 665948070 + ... + 665948389.
It is an arithmetic number, because the mean of its divisors is an integer number (20977369245).
Almost surely, 2213103433440 is an apocalyptic number.
213103433440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213103433440 is an abundant number, since it is smaller than the sum of its proper divisors (290353428440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213103433440 is a wasteful number, since it uses less digits than its factorization.
213103433440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1331896474 (or 1331896466 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 213103433440 its reverse (44334301312), we get a palindrome (257437734752).
The spelling of 213103433440 in words is "two hundred thirteen billion, one hundred three million, four hundred thirty-three thousand, four hundred forty".
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