Base | Representation |
---|---|
bin | 11111000000101100000… |
… | …101100001010011010000 |
3 | 21112201121002011111110111 |
4 | 133000230011201103100 |
5 | 234403334104022230 |
6 | 4310553212211104 |
7 | 306651146140201 |
oct | 37005405412320 |
9 | 7481532144414 |
10 | 2131043423440 |
11 | 751852502438 |
12 | 2a5016169a94 |
13 | 125c5866ac09 |
14 | 7520076b5a8 |
15 | 3a67774d92a |
hex | 1f02c1614d0 |
2131043423440 has 80 divisors (see below), whose sum is σ = 5211004617216. Its totient is φ = 809355456000.
The previous prime is 2131043423393. The next prime is 2131043423441. The reversal of 2131043423440 is 443243401312.
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131043423441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7975086 + ... + 8237965.
Almost surely, 22131043423440 is an apocalyptic number.
2131043423440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2131043423440 is an abundant number, since it is smaller than the sum of its proper divisors (3079961193776).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131043423440 is a wasteful number, since it uses less digits than its factorization.
2131043423440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16213148 (or 16213142 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 2131043423440 its reverse (443243401312), we get a palindrome (2574286824752).
The spelling of 2131043423440 in words is "two trillion, one hundred thirty-one billion, forty-three million, four hundred twenty-three thousand, four hundred forty".
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