Base | Representation |
---|---|
bin | 1100011001111001101… |
… | …0011000000110101110 |
3 | 202101002002011012010020 |
4 | 3012132122120012232 |
5 | 11442422421041420 |
6 | 241522450423010 |
7 | 21253043364441 |
oct | 3063632300656 |
9 | 671062135106 |
10 | 213111112110 |
11 | 8241a737846 |
12 | 35376591a66 |
13 | 17133725490 |
14 | a4594d1658 |
15 | 5824523340 |
hex | 319e6981ae |
213111112110 has 64 divisors (see below), whose sum is σ = 551252520000. Its totient is φ = 52416000000.
The previous prime is 213111112103. The next prime is 213111112127. The reversal of 213111112110 is 11211111312.
213111112110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2131111121102 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 213111112110.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 268360 + ... + 705860.
It is an arithmetic number, because the mean of its divisors is an integer number (8613320625).
Almost surely, 2213111112110 is an apocalyptic number.
213111112110 is an abundant number, since it is smaller than the sum of its proper divisors (338141407890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213111112110 is a wasteful number, since it uses less digits than its factorization.
213111112110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 438773.
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 213111112110 its reverse (11211111312), we get a palindrome (224322223422).
It can be divided in two parts, 213111 and 112110, that added together give a triangular number (325221 = T806).
The spelling of 213111112110 in words is "two hundred thirteen billion, one hundred eleven million, one hundred twelve thousand, one hundred ten".
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