213111113114040 has 128 divisors (see below), whose sum is σ = 647440846848000. Its totient is φ = 56108995458048.

The previous prime is 213111113114021. The next prime is 213111113114059. The reversal of 213111113114040 is 40411311111312.

It is an interprime number because it is at equal distance from previous prime (213111113114021) and next prime (213111113114059).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 213111113114040.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 462080676 + ... + 462541644.

It is an arithmetic number, because the mean of its divisors is an integer number (5058131616000).

Almost surely, 2^{213111113114040} is an apocalyptic number.

213111113114040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

213111113114040 is an abundant number, since it is smaller than the sum of its proper divisors (434329733733960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213111113114040 is a wasteful number, since it uses less digits than its factorization.

213111113114040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509829 (or 509825 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 24.

Adding to 213111113114040 its reverse (40411311111312), we get a palindrome (253522424225352).

The spelling of 213111113114040 in words is "two hundred thirteen trillion, one hundred eleven billion, one hundred thirteen million, one hundred fourteen thousand, forty".