Base | Representation |
---|---|
bin | 1001101100001111011010… |
… | …01000111111000111010000 |
3 | 2210110100012221001002221220 |
4 | 10312013231020333013100 |
5 | 10243131031143430222 |
6 | 113154140430245040 |
7 | 4326456106166301 |
oct | 466075510770720 |
9 | 83410187032856 |
10 | 21311311311312 |
11 | 68770927178a0 |
12 | 2482337056780 |
13 | bb7856963c99 |
14 | 539689b927a8 |
15 | 26e551d40b5c |
hex | 1361ed23f1d0 |
21311311311312 has 40 divisors (see below), whose sum is σ = 60059150060640. Its totient is φ = 6457973124480.
The previous prime is 21311311311263. The next prime is 21311311311343.
21311311311312 is nontrivially palindromic in base 10.
It is a super-2 number, since 2×213113113113122 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20181165487 + ... + 20181166542.
It is an arithmetic number, because the mean of its divisors is an integer number (1501478751516).
Almost surely, 221311311311312 is an apocalyptic number.
21311311311312 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
21311311311312 is an abundant number, since it is smaller than the sum of its proper divisors (38747838749328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21311311311312 is a wasteful number, since it uses less digits than its factorization.
21311311311312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40362332051 (or 40362332045 counting only the distinct ones).
The product of its digits is 324, while the sum is 24.
It can be divided in two parts, 2131131 and 1311312, that added together give a palindrome (3442443).
The spelling of 21311311311312 in words is "twenty-one trillion, three hundred eleven billion, three hundred eleven million, three hundred eleven thousand, three hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •