Base | Representation |
---|---|
bin | 11111000000110110110… |
… | …010101000011001100111 |
3 | 21112202001121010000012212 |
4 | 133000312302220121213 |
5 | 234404221043134114 |
6 | 4311023105434035 |
7 | 306655456531541 |
oct | 37006662503147 |
9 | 7482047100185 |
10 | 2131223021159 |
11 | 75193491a901 |
12 | 2a506633b91b |
13 | 125c8693095b |
14 | 7521a55c691 |
15 | 3a6883c7b3e |
hex | 1f036ca8667 |
2131223021159 has 2 divisors, whose sum is σ = 2131223021160. Its totient is φ = 2131223021158.
The previous prime is 2131223021153. The next prime is 2131223021269. The reversal of 2131223021159 is 9511203221312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131223021159 - 216 = 2131222955623 is a prime.
It is a super-2 number, since 2×21312230211592 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131223021153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065611510579 + 1065611510580.
It is an arithmetic number, because the mean of its divisors is an integer number (1065611510580).
Almost surely, 22131223021159 is an apocalyptic number.
2131223021159 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131223021159 is an equidigital number, since it uses as much as digits as its factorization.
2131223021159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 2131223021159 in words is "two trillion, one hundred thirty-one billion, two hundred twenty-three million, twenty-one thousand, one hundred fifty-nine".
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