Base | Representation |
---|---|
bin | 11111000001111110001… |
… | …101110010001001111101 |
3 | 21112212011002220222001002 |
4 | 133001332031302021331 |
5 | 234414144324240331 |
6 | 4311342033300045 |
7 | 310030250110223 |
oct | 37017615621175 |
9 | 7485132828032 |
10 | 2132421321341 |
11 | 75239a275533 |
12 | 2a533b704625 |
13 | 126117c7b50c |
14 | 752d1768b13 |
15 | 3a7086c99cb |
hex | 1f07e37227d |
2132421321341 has 2 divisors, whose sum is σ = 2132421321342. Its totient is φ = 2132421321340.
The previous prime is 2132421321313. The next prime is 2132421321361. The reversal of 2132421321341 is 1431231242312.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1255417166116 + 877004155225 = 1120454^2 + 936485^2 .
It is a cyclic number.
It is not a de Polignac number, because 2132421321341 - 210 = 2132421320317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132421321361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066210660670 + 1066210660671.
It is an arithmetic number, because the mean of its divisors is an integer number (1066210660671).
Almost surely, 22132421321341 is an apocalyptic number.
It is an amenable number.
2132421321341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132421321341 is an equidigital number, since it uses as much as digits as its factorization.
2132421321341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 2132421321341 its reverse (1431231242312), we get a palindrome (3563652563653).
The spelling of 2132421321341 in words is "two trillion, one hundred thirty-two billion, four hundred twenty-one million, three hundred twenty-one thousand, three hundred forty-one".
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