Base | Representation |
---|---|
bin | 11111000001111111100… |
… | …001010010101001110000 |
3 | 21112212012122010010221001 |
4 | 133001333201102221300 |
5 | 234414220430244100 |
6 | 4311344134411344 |
7 | 310030634143444 |
oct | 37017741225160 |
9 | 7485178103831 |
10 | 2132443212400 |
11 | 752400667616 |
12 | 2a5346b00b54 |
13 | 12611c6745c7 |
14 | 752d4626824 |
15 | 3a70a5a0d6a |
hex | 1f07f852a70 |
2132443212400 has 30 divisors (see below), whose sum is σ = 5123194818752. Its totient is φ = 852977284800.
The previous prime is 2132443212373. The next prime is 2132443212407. The reversal of 2132443212400 is 42123442312.
It is a super-2 number, since 2×21324432124002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132443212407) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2665553616 + ... + 2665554415.
Almost surely, 22132443212400 is an apocalyptic number.
2132443212400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2132443212400 is an abundant number, since it is smaller than the sum of its proper divisors (2990751606352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2132443212400 is a wasteful number, since it uses less digits than its factorization.
2132443212400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5331108049 (or 5331108038 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 2132443212400 its reverse (42123442312), we get a palindrome (2174566654712).
The spelling of 2132443212400 in words is "two trillion, one hundred thirty-two billion, four hundred forty-three million, two hundred twelve thousand, four hundred".
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