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213320132017 is a prime number
BaseRepresentation
bin1100011010101011011…
…1101110010110110001
3202101121122110111112021
43012222313232112301
511443334423211032
6241555314431441
721261162130066
oct3065267562661
9671548414467
10213320132017
1182517720573
1235414592581
1317167b1a1b5
14a479180c6d
155837a60097
hex31aadee5b1

213320132017 has 2 divisors, whose sum is σ = 213320132018. Its totient is φ = 213320132016.

The previous prime is 213320131993. The next prime is 213320132021. The reversal of 213320132017 is 710231023312.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 153727510561 + 59592621456 = 392081^2 + 244116^2 .

It is a cyclic number.

It is not a de Polignac number, because 213320132017 - 219 = 213319607729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213320131982 and 213320132000.

It is not a weakly prime, because it can be changed into another prime (213320132617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106660066008 + 106660066009.

It is an arithmetic number, because the mean of its divisors is an integer number (106660066009).

Almost surely, 2213320132017 is an apocalyptic number.

It is an amenable number.

213320132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

213320132017 is an equidigital number, since it uses as much as digits as its factorization.

213320132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 213320132017 its reverse (710231023312), we get a palindrome (923551155329).

The spelling of 213320132017 in words is "two hundred thirteen billion, three hundred twenty million, one hundred thirty-two thousand, seventeen".