213320132021 has 2 divisors, whose sum is σ = 213320132022. Its totient is φ = 213320132020.

The previous prime is 213320132017. The next prime is 213320132023. The reversal of 213320132021 is 120231023312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 157014062500 + 56306069521 = 396250^2 + 237289^2 .

It is a cyclic number.

It is not a de Polignac number, because 213320132021 - 2² = 213320132017 is a prime.

Together with 213320132023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 213320131984 and 213320132002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213320132023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106660066010 + 106660066011.

It is an arithmetic number, because the mean of its divisors is an integer number (106660066011).

Almost surely, 2^213320132021 is an apocalyptic number.

It is an amenable number.

213320132021 is a deficient number, since it is larger than the sum of its proper divisors (1).

213320132021 is an equidigital number, since it uses as much as digits as its factorization.

213320132021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 213320132021 its reverse (120231023312), we get a palindrome (333551155333).

The spelling of 213320132021 in words is "two hundred thirteen billion, three hundred twenty million, one hundred thirty-two thousand, twenty-one".