Base | Representation |
---|---|
bin | 1100011011000110101… |
… | …0001011101000000111 |
3 | 202101220120202201202212 |
4 | 3012301222023220013 |
5 | 11444103102204112 |
6 | 242014503454035 |
7 | 21264044154044 |
oct | 3066152135007 |
9 | 671816681685 |
10 | 213434022407 |
11 | 82575a3a061 |
12 | 3544675731b |
13 | 171855b5268 |
14 | a48a34a1cb |
15 | 5842a5a522 |
hex | 31b1a8ba07 |
213434022407 has 2 divisors, whose sum is σ = 213434022408. Its totient is φ = 213434022406.
The previous prime is 213434022299. The next prime is 213434022409. The reversal of 213434022407 is 704220434312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213434022407 - 212 = 213434018311 is a prime.
Together with 213434022409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213434022409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106717011203 + 106717011204.
It is an arithmetic number, because the mean of its divisors is an integer number (106717011204).
Almost surely, 2213434022407 is an apocalyptic number.
213434022407 is a deficient number, since it is larger than the sum of its proper divisors (1).
213434022407 is an equidigital number, since it uses as much as digits as its factorization.
213434022407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 32.
Adding to 213434022407 its reverse (704220434312), we get a palindrome (917654456719).
The spelling of 213434022407 in words is "two hundred thirteen billion, four hundred thirty-four million, twenty-two thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •