Search a number
-
+
213434022407 is a prime number
BaseRepresentation
bin1100011011000110101…
…0001011101000000111
3202101220120202201202212
43012301222023220013
511444103102204112
6242014503454035
721264044154044
oct3066152135007
9671816681685
10213434022407
1182575a3a061
123544675731b
13171855b5268
14a48a34a1cb
155842a5a522
hex31b1a8ba07

213434022407 has 2 divisors, whose sum is σ = 213434022408. Its totient is φ = 213434022406.

The previous prime is 213434022299. The next prime is 213434022409. The reversal of 213434022407 is 704220434312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213434022407 - 212 = 213434018311 is a prime.

Together with 213434022409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213434022409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106717011203 + 106717011204.

It is an arithmetic number, because the mean of its divisors is an integer number (106717011204).

Almost surely, 2213434022407 is an apocalyptic number.

213434022407 is a deficient number, since it is larger than the sum of its proper divisors (1).

213434022407 is an equidigital number, since it uses as much as digits as its factorization.

213434022407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 32.

Adding to 213434022407 its reverse (704220434312), we get a palindrome (917654456719).

The spelling of 213434022407 in words is "two hundred thirteen billion, four hundred thirty-four million, twenty-two thousand, four hundred seven".