Base | Representation |
---|---|
bin | 110000101010101111011110… |
… | …101111010011110011100000 |
3 | 1001001212100111210210022210201 |
4 | 300222233132233103303200 |
5 | 211023341422111440000 |
6 | 2035122110102034544 |
7 | 63041061533044141 |
oct | 6052573657236340 |
9 | 1031770453708721 |
10 | 214043432140000 |
11 | 62223345384611 |
12 | 2000b074418a54 |
13 | 9258294362248 |
14 | 3abda863d5ac8 |
15 | 19b2b62e2996a |
hex | c2abdebd3ce0 |
214043432140000 has 120 divisors (see below), whose sum is σ = 549473687698320. Its totient is φ = 81894878208000.
The previous prime is 214043432139989. The next prime is 214043432140019. The reversal of 214043432140000 is 41234340412.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 232195905 + ... + 233115904.
It is an arithmetic number, because the mean of its divisors is an integer number (4578947397486).
Almost surely, 2214043432140000 is an apocalyptic number.
214043432140000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
214043432140000 is an abundant number, since it is smaller than the sum of its proper divisors (335430255558320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
214043432140000 is an equidigital number, since it uses as much as digits as its factorization.
214043432140000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 465311862 (or 465311839 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 214043432140000 its reverse (41234340412), we get a palindrome (214084666480412).
The spelling of 214043432140000 in words is "two hundred fourteen trillion, forty-three billion, four hundred thirty-two million, one hundred forty thousand".
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