Base | Representation |
---|---|
bin | 1001101110111100111000… |
… | …00111110100010111000100 |
3 | 2210210020121022121022002112 |
4 | 10313132130013310113010 |
5 | 10301142243440044030 |
6 | 113305021542000152 |
7 | 4336264003251140 |
oct | 467363407642704 |
9 | 83706538538075 |
10 | 21404441331140 |
11 | 690263313412a |
12 | 24983a8116058 |
13 | bc35790922aa |
14 | 53dda2660220 |
15 | 271ba2d95a95 |
hex | 13779c1f45c4 |
21404441331140 has 96 divisors (see below), whose sum is σ = 52187001345024. Its totient is φ = 7222881300480.
The previous prime is 21404441331137. The next prime is 21404441331151. The reversal of 21404441331140 is 4113314440412.
It is a junction number, because it is equal to n+sod(n) for n = 21404441331097 and 21404441331106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1896092 + ... + 6812051.
It is an arithmetic number, because the mean of its divisors is an integer number (543614597344).
Almost surely, 221404441331140 is an apocalyptic number.
21404441331140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21404441331140 is an abundant number, since it is smaller than the sum of its proper divisors (30782560013884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21404441331140 is a wasteful number, since it uses less digits than its factorization.
21404441331140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8708437 (or 8708435 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 21404441331140 its reverse (4113314440412), we get a palindrome (25517755771552).
The spelling of 21404441331140 in words is "twenty-one trillion, four hundred four billion, four hundred forty-one million, three hundred thirty-one thousand, one hundred forty".
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