Base | Representation |
---|---|
bin | 11111001010000011101… |
… | …111101100001011010111 |
3 | 21120200120012222021201221 |
4 | 133022003233230023113 |
5 | 240034440112433143 |
6 | 4315335402031211 |
7 | 310455360654661 |
oct | 37120357541327 |
9 | 7520505867657 |
10 | 2141104030423 |
11 | 756045452366 |
12 | 2a6b634a8507 |
13 | 126b9ca886b7 |
14 | 758b6989531 |
15 | 3aa65ace2ed |
hex | 1f283bec2d7 |
2141104030423 has 2 divisors, whose sum is σ = 2141104030424. Its totient is φ = 2141104030422.
The previous prime is 2141104030421. The next prime is 2141104030433. The reversal of 2141104030423 is 3240304011412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2141104030423 - 21 = 2141104030421 is a prime.
It is a super-3 number, since 3×21411040304233 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 2141104030421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2141104030421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070552015211 + 1070552015212.
It is an arithmetic number, because the mean of its divisors is an integer number (1070552015212).
Almost surely, 22141104030423 is an apocalyptic number.
2141104030423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141104030423 is an equidigital number, since it uses as much as digits as its factorization.
2141104030423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2141104030423 its reverse (3240304011412), we get a palindrome (5381408041835).
The spelling of 2141104030423 in words is "two trillion, one hundred forty-one billion, one hundred four million, thirty thousand, four hundred twenty-three".
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