Base | Representation |
---|---|
bin | 1100011110000010010… |
… | …1011100111000001111 |
3 | 202110221110012011101021 |
4 | 3013200211130320033 |
5 | 12002211123432003 |
6 | 242224550055011 |
7 | 21322414050403 |
oct | 3074045347017 |
9 | 673843164337 |
10 | 214221311503 |
11 | 8293a389001 |
12 | 3562634a467 |
13 | 1727c7376b4 |
14 | a522b27103 |
15 | 588bc212bd |
hex | 31e095ce0f |
214221311503 has 2 divisors, whose sum is σ = 214221311504. Its totient is φ = 214221311502.
The previous prime is 214221311501. The next prime is 214221311539. The reversal of 214221311503 is 305113122412.
214221311503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214221311503 - 21 = 214221311501 is a prime.
Together with 214221311501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214221311501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107110655751 + 107110655752.
It is an arithmetic number, because the mean of its divisors is an integer number (107110655752).
Almost surely, 2214221311503 is an apocalyptic number.
214221311503 is a deficient number, since it is larger than the sum of its proper divisors (1).
214221311503 is an equidigital number, since it uses as much as digits as its factorization.
214221311503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 214221311503 its reverse (305113122412), we get a palindrome (519334433915).
The spelling of 214221311503 in words is "two hundred fourteen billion, two hundred twenty-one million, three hundred eleven thousand, five hundred three".
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