Base | Representation |
---|---|
bin | 11111001100110111101… |
… | …110000011011001011101 |
3 | 21120222100122122020111010 |
4 | 133030313232003121131 |
5 | 240112131104001000 |
6 | 4320555143445433 |
7 | 310623244020435 |
oct | 37146756033135 |
9 | 7528318566433 |
10 | 2144123500125 |
11 | 757354900672 |
12 | 2a7666756879 |
13 | 1272614c8b69 |
14 | 75ac19bd2c5 |
15 | 3ab90c1bd50 |
hex | 1f337b8365d |
2144123500125 has 128 divisors (see below), whose sum is σ = 3836690178048. Its totient is φ = 1060716096000.
The previous prime is 2144123500097. The next prime is 2144123500201. The reversal of 2144123500125 is 5210053214412.
It is not a de Polignac number, because 2144123500125 - 25 = 2144123500093 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2144123500092 and 2144123500101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 59037222 + ... + 59073528.
It is an arithmetic number, because the mean of its divisors is an integer number (29974142016).
Almost surely, 22144123500125 is an apocalyptic number.
2144123500125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2144123500125 is a deficient number, since it is larger than the sum of its proper divisors (1692566677923).
2144123500125 is a wasteful number, since it uses less digits than its factorization.
2144123500125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36556 (or 36546 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 2144123500125 its reverse (5210053214412), we get a palindrome (7354176714537).
The spelling of 2144123500125 in words is "two trillion, one hundred forty-four billion, one hundred twenty-three million, five hundred thousand, one hundred twenty-five".
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